Addresses on N Searcy Ave, Bartow, Polk County, FL
N Searcy Ave, Bartow, Polk County, FL has 5 properties on TopHap. The typical one has 1,852 ft² of living area, 2 bedrooms, 1 bathrooms, and a 0.33 acre lot. It is built in 1930, valued at $295,941, and $167 per ft².
- Properties
- 5
- Addresses
- 5
- Median living area
- 1,852 ft²
- Median bedrooms
- 2
- Median bathrooms
- 1
- Median lot size
- 0.33 ac
- Median year built
- 1930
- Median estimate
- $295,941
- Median price / ft²
- $167 / ft²
All 5 addresses
- 390 N Searcy Ave2 ba · 1,572 ft² · 0.22 ac lot · built 1930
- 410 N Searcy Ave3 bd · 1 ba · 1,852 ft² · 0.54 ac lot · built 1920 · est. $343,129
- 490 N Searcy Ave3 bd · 1 ba · 1,680 ft² · 0.27 ac lot · built 1888 · est. $248,752
- 505 N Searcy Ave2 bd · 1 ba · 2,280 ft² · 0.33 ac lot · built 1981
- 595 N Searcy Ave2 bd · 1 ba · 2,280 ft² · 0.33 ac lot · built 1980
Characteristics and valuations come from county assessor and recorder records. Browse all states.